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Q&A for How to Find the Magnitude of a Vector
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QuestionThe coordinates of head and tail of a vector are (2, 1, 0), (-4, 2, -3). What is the magnitude of the vector?Community AnswerYou can use the same formula: |→a| = √((x2 – x1)^2 + (y2 – y1)^2), but add on (z2 – z1)^2 at the end for the third set of coordinates!
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QuestionHow do I find the direction?Community AnswerUse this formula: tan(y component / x component). If the vector is in quadrant 3 or 4, add a half rotation.
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QuestionWhat is the magnitude of the resultant vector of vector A-12.66 and vector B-11.93?Community AnswerTo get the magnitude you need to square both the vectors' magnitude and then take the underroot.
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QuestionHow do I find the magnitude of a vertical and horizontal component if a vector is shown in a scale diagram?Community AnswerIf you're given an angle, use that angle and the vector's magnitude to calculate. Vx= (vector's mag)*cos(angle), Vy= (vector's mag)*sin(angle).
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QuestionHow can I find the magnitude of vectors if there is no coordinates, an angle, and then a force?Community AnswerIf you are given a value for work, you can divide that value by the magnitude of the force multiplied by the cosine of the angle, since W=|F||d|cos⍺ (|d|=W/(|F|cos⍺)).
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QuestionHow do I find the vector when only its modulus is given?Community AnswerOne modulus can apply to more than one vector, so any coordinates that fit the formula |a|= square root of (x^2 = y^2) should work, where |a|= the magnitude/modulus.
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QuestionHow do I find the angle between two vectors?DonaganTop Answerer
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QuestionHow do I find the magnitude of vector AB when A is at (-4,-6) and B is at (1,-3)?DonaganTop AnswererSubtract 1 from -4 to get -5 and square it to get 25. Subtract -3 from -6 to get -3 and square it to get 9. Add 25 and 9 to get 34. The square root of 34 is approximately 5.83, which is the magnitude of vector AB.
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