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Have you ever had a simultaneous problem equation you needed to solve? When you use the elimination method, you can achieve a desired result in a very short time. This article can explain how to perform to achieve the solution for both variables.

  1. [1]
    • 3x - y = 12
    • 2x + y = 13
  2. 3x - y = 12 as number one, and 2x + y = 13 as number two. [2]
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  3. [3]
  4. Divide both sides by the coefficient of the left side. Take 5 to the other side.It will look like this:x = 25/5. [5]
  5. Use the value of x that was obtained above into either equation (but stick with this equation for the time being). Substitute this value of x into the equation. [6]
  6. Substitute both the values into the other equation. If the two side numbers at the very end equal each other, you've correctly solved this system of simultaneous equations. [7]
    • 3x - y = 12
    • 3(5) - 3 = 12
    • 15 - 3 = 12
    • 12 = 12
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  • Question
    How do I find the first term and the constant difference of simultaneous equations?
    Donagan
    Top Answerer
    "First term" and "constant difference" do not apply to simultaneous equations. (They are used in arithmetic sequences.)
  • Question
    Is this useful in all the countries? Where I live, we work our equations very differently.
    Donagan
    Top Answerer
    Mathematics knows no national boundaries. There is more than one method of solving simultaneous equations, and all methods are known and "useful" in every country. Apparently you were not taught the elimination method in school.
  • Question
    How do I work with fractions in solving simultaneous equations using elimination method?
    Donagan
    Top Answerer
    The process is the same as outlined above, except that you would have to clear a fraction when solving for a variable. For example, you may see something like 5x/2 = 10, in which case you would just multiply both sides of that equation by 2 and then divide both sides by 5.
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      Tips

      • You can solve it horizontally as well.
      • Remember that if the unknown terms have the same signs you must subtract and if they have different signs you must add the equations.
      • The easiest of all is the elimination method and fastest as well. It is simple and can be learned much more easily then the other two. It is usually used when the equations have the same variable/unknown term disregarding the sign.
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