Q&A for How to Add 5 Consecutive Numbers Quickly

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What are five consecutive whole numbers that add up to 50?

Donagan

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Let n be the first number. Then (n) + (n+1) + (n+2) + (n+3) + (n+4) = 50. Combining terms, 5n + 10 = 50. Then 5n = 40, and n = 8. The numbers are 8, 9, 10, 11 and 12.

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What are 5 consecutive whole numbers that equal 15?

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First divide 15 by 5 to get the middle number in the sequence. Since there are 5 numbers in the sequence used, we divide by 5. This gives us the number three. We know that this is the middle number in the sequence, so there are an equal amount of numbers both above and below this. Therefore, the numbers must be 1,2,3,4,5. Those five numbers add up to 15 to confirm that this answer is correct.

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The sum of five consecutive numbers is 100. How do I find the first number?

Donagan

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Let n be the first number. Then the next four numbers will be n+1, n+2, n+3, and n+4. Add the five numbers together and set them equal to 100: (n) + (n+1) + (n+2) + (n+3) +(n+4) = 100. Add together the five terms on the left to get 5n + 10 and let that equal 100: 5n +10 = 100. Subtract 10 from both sides: 5n = 90. Divide both sides by 5: n = 18. That's the number you're looking for.

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Rhoda draws a number inside the box. If there are numbers 1-50 what is the possibility of getting 25?

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The possibility of getting 25 would be one in 50. This sounds like a homework question; don't use wikiHow to do your homework for you. You can ask about concepts you don't understand, but not to answer your homework problems.

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What are 5 consecutive whole numbers that equal 40?

Donagan

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Using Method 1 above, let 5n = 40, where n is the middle number of the five consecutive numbers. Solve for n, and go from there.

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When 5 consecutive integers are added together and the sum is then multiplied by 5, the result is 225. What is the largest of the 5 consecutive integers?

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To solve this, work backwards on the problem. The sum times 5 is equal to 225. 225 / 5 = 45, which is the sum we are trying to find. What are the 5 integers used to produce 45? They will have an average of 45 / 5, which is 9. 9 plus the 2 numbers on either side of it are 7, 8, 9, 10, 11, which equal 45 when added. Therefore, the largest of the 5 integers is 11.

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Five consecutive numbers are 80. How do I find the numbers?

Donagan

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Find the middle number by dividing 80 by 5. That's 16. Then the other four numbers are 14, 15, 17 and 18.

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What are 5 consecutive even numbers used to make 80?

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12 + 14 + 16 + 18 + 20. 80 / 5 = 16, so the required numbers are the two consecutive even numbers before 16, then 16, then the two consecutive even numbers after 16.

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If five consecutive integers multiplied is 120, what is the largest number?

Donagan

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The first five consecutive, positive integers (1, 2, 3, 4, and 5) multiply together to make 120. The largest of those integers is 5.

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The sum of five consecutive integers is 0. How do I solve?

Donagan

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If you're asking which five consecutive integers have a sum of zero, by inspection it's apparent that some of the integers would have to be negative and some positive in order to offset each other to the point that the sum is zero. Zero would have to be the middle number so that the other numbers will balance each other perfectly. Thus, the integers are -2, -1, 0, +1 and +2 (and yes, zero is an integer).

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How do I solve 4x - 3/2 - 8x - 10/8 = 2 3/4?

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First change all fractions so that they have the same denominator: 4x - 6/4 - 8x - 5/4 = 2 3/4 = 11/4. Now combine like terms: -4x - 11/4 = 11/4. Isolate the variable: -4x = 22/4. Divide both sides by -4: x = -22/16 = -11/8 = -1 3/8.

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What are five consecutive whole numbers that add up to 1,000?

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Let x be the smallest number. Then (x) + (x + 1) + (x + 2) + (x + 3) + (x + 4) = 1,000. Combining terms, 5x + 10 = 1,000. 5x = 990, and x = 198. So the numbers are 198, 199, 200, 201 and 202.

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