wikiHow Calculating Tension Practice Answers 1. Tension (T) = Weight of the block = mg = 2 kg x 9.8 m/s^2 = 19.6 N Therefore, the tension in the rope is 19.6 N. 2. Tension (T) = Applied force = 50 N Therefore, the tension in the rope is 50 N. 3. Tension (T) = F1 + F2 = 80 N + 60 N = 140 N Therefore, the tension in the rope is 140 N. 4. Tension (T) = (m x g x sinθ) + (m x g x cosθ x μ) = (4 kg x 9.8 m/s^2 x sin 30°) + (4 kg x 9.8 m/s^2 x cos 30° x 0.2) = 15.7 N + 5.66 N Therefore, the tension in the rope is 21.4 N. 5. Tension (T) = Weight of the block = mg = 20 kg x 9.8 m/s^2 = 196 N Therefore, the tension in the rope is 196 N. 6. Tension (T) = Applied force - Frictional force = 30 N - (5 kg x 9.8 m/s^2 x 0.5) = 5 N Therefore, the tension in the rope is 5 N. 7. Tension (T) = Weight of the block / (2 x sin 60°) = (1 kg x 9.8 m/s^2) / (2 x sin 60°) = 5.66 N Therefore, the tension in each rope is 5.66 N. 8. Tension (T) = (m x g x sinθ) + (m x g x cosθ x μ) = (50 kg x 9.8 m/s^2 x sin 20°) + (50 kg x 9.8 m/s^2 x cos 20° x 0.3) = 160.8 N Therefore, the tension in the rope is 160.8 N. 9. Tension (T) = Applied force = 100 N Therefore, the tension in the rope is 100 N. 10. Tension (T) = Weight of the block + (m x a) = (10 kg x 9.8 m/s^2) + (10 kg x 2 m/s^2) = 196 N + 20 N Therefore, the tension in the rope is 216 N. 11. Tension (T) = F1 + F2 = 80 N + 60 N = 140 N Therefore, the tension in the rope is 140 N. 12. Tension (T) = Weight of the block / (2 x sin 90°) = (3 kg x 9.8 m/s^2) / (2 x sin 90°) = 14.7 N Therefore, the tension in each rope is 14.7 N. 13. Tension (T) = Applied force - Frictional force = 200 N - (50 kg x 9.8 m/s^2 x 0.4) = 180.8 N Therefore, the tension in the rope is 180.8 N. 14. Tension (T) = Applied force = 20 N Therefore, the tension in the rope is 20 N. 15. Tension (T) = Weight of the block - (m x a) = (5 kg x 9.8 m/s^2) - (5 kg x 3 m/s^2) = 49 N - 15 N Therefore, the tension in the rope is 34 N. 16. Tension (T) = Applied force + (m x a) = 100 N + (5 kg x 4 m/s^2) = 120 N Therefore, the tension in the rope is 120 N. 17. Tension (T) = F1 - F2 = 120 N - 80 N = 40 N Therefore, the tension in the rope is 40 N. 18. Tension (T) = Weight of the block / (2 x sin 60°) = (2 kg x 9.8 m/s^2) / (2 x sin 60°) = 11.2 N Therefore, the tension in the rope is 11.2 N. 19. T = (0.2 x 10 kg x 9.8 m/s^2 x cos(40°)) + (10 kg x 9.8 m/s^2 x sin(40°)) / sin(40°) = 111.3 N 20. T = F_friction = friction coefficient x mg = 0.4 x 5 kg x 9.8 m/s^2 = 19.6 N Page