Q&A for How to Find the Perimeter of a Rectangle

When dealing with a rectangle, you can find the length of the missing side by utilizing division or by manipulating the equation through your understanding of literal equations. In the context of triangles, a similar principle applies. If you know the area and the lengths of two sides of a triangle, you can employ appropriate formulas, such as the formula for the area of a triangle. To solve for the length of the missing side, the Pythagorean theorem is commonly used for right-angled triangles, and trigonometric ratios can be employed for various types of triangles. It ultimately depends on the specifics of the triangle in question.

You can't. With any given perimeter, an infinite number of length-width combinations would be possible.

It can help to break difficult shapes up into simpler shapes. Use area formulas for these simpler shapes to help you find all the side lengths of the complex shape.

No, the "oddness" of the shape makes it impossible to know the perimeter without more information.

Let L be the length. Then (L - 4) is the breadth. The perimeter is twice the length plus twice the breadth: 2 (L) + 2 (L - 4) = 40. Solve for L. The breadth will be 4 less than L.

To find the perimeter of a rectangle with a trinomial equation as the area, you'll need to factor this equation to get the sides. Once you've factored the equation, you can then add the sides to find the perimeter.

A = 294 m^2 = 3x*2x = 6x^2 for some x So x = 7m Perimeter= 2(3x + 2x), so plugging in the now known value x=7m yields P = 70m

If you assume that the length and width are both 9, you could easily find the perimeter. However, you can't really assume the length and width are each 9, so you don't actually have enough information to calculate the perimeter.

No, if you don't know any of the sides, you can't find the perimeter.

Divide the area by the length. That gives you the width. Find the perimeter by adding twice the length to twice the width.

Add 32 and 48.

The width is x, and the length is (x + 40%). (x + 40%) = (x + 0.4x) = 1.4x. The perimeter is twice the width plus twice the length, which is (2x) + 2(1.4x) = (2x) + (2.8x) = 4.8x.

Let w be the width. Then the length is (w + 48). The perimeter is twice the width plus twice the length, or 2w + 2(w+48) = 2w + (2w + 96) = 4w + 96 = 840. Then 4w = 744, and w = 186 m.

Use the Pythagorean theorem to find the length. (Square the diagonal, and from that subtract the square of the width. That gives you the square of the length, so find its square root.) Once you know the length, double it, and add twice the width. That's the perimeter.

If you're asking about the perimeter of a square, first find the square root of its area. That gives you the length of any side. Multiply that length by 4 to get the perimeter.

It can't be done, because a rectangle with a given area could have several different length/width combinations (leading to different perimeters).

The "height" of a rectangle is also referred to as it width. As shown above, a rectangle's perimeter is twice its length plus twice its width.

If it's a square, you could square root the area. The area of a square is equal to length * width. Since the sides are the same you can just square root the area to get the length and width of the square. If it's a rectangle, use equations to solve it. L (length) * W (width) = (insert the area). 2L + 2W = (insert the perimeter). Then test different lengths and widths that multiply to the area, and equal the perimeter when you apply the 2L + 2W perimeter formula.

Divide the area by the length. That gives you the breadth (width). Add twice the breadth to twice the length to get the perimeter.

Let x be the width. Then (x + 3) is the length. So 21 = 2x + 2(x + 3) = 2x + 2x + 6 = 4x + 6. 21 = 4x + 6. Subtract 6 from both sides of the equation: 15 = 4x. Divide both sides by 4: x = 15/4 = 3 3/4 inches. That's the width. (To check the answer: the length is 3 3/4 + 3 = 6 3/4. Then the perimeter is 2(3¾) + 2(6¾) = 7½ + 13½ = 21.)