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QuestionHow would I find width when I've been given volume, height, and length?Blankless XCommunity AnswerYou divide the volume by the height and the length. You could multiply the height and the length with each other first before dividing. W = V / (H*L).
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QuestionThe length of a rectangle field is twice its breadth. Its perimeter is 400m. How do I find the length and breadth?DonaganTop AnswererLet B equal the breadth. Then 2B equals the length. Write an equation in B, stating that the perimeter is equal to twice the breadth plus twice the length. Solve for B.
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QuestionHow do I find the area of a rectangle if width and perimeter are given?DonaganTop AnswererDouble the width, and subtract that from the perimeter. Then divide that number by two, which gives you the length of the rectangle. Then, multiply the result by the width to get the area.
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QuestionHow do I find the dimensions of a rectangle if the perimeter is 33 and the length equals twice the width?DonaganTop AnswererThe length (l) is twice the width (w), so l = 2w. The perimeter, or twice the length plus twice the width, is 33, so 2(2w) + 2w = 33. That means 6w = 33; w = 5½, and 2w = l = 11.
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QuestionArea = 40" and perimeter = 28"; how do I find side lengths of a rectangle?DonaganTop AnswererLet x and y be the dimensions of the rectangle. Then xy = 40, and 2x + 2y = 28. From the first equation, x = 40/y. Substituting that value of x into the second equation, 2(40/y) + 2y = (80/y) + 2y = 28. Multiply both sides of this equation by y to get rid of the denominator: 80 + 2y² = 28y. Divide by 2 to simplify: 40 + y² = 14y. Subtract 14y from both sides to get zero on one side, and re-arrange slightly: y² - 14y + 40 = 0. Factor the left side: (y - 10)(y - 4) = 0. Set each factor equal to zero to solve for y: y = 4, 10. That means that one side of the rectangle is 4 inches in length, and the other side is 10 inches.
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QuestionThe area is 77 m^2, but all I know about the length is that it's 4 m longer than the width. How do I find the width?DonaganTop AnswererSet up an equation in which the width (w) is multiplied by four-more-than-the-width (w + 4) to equal 77. Then solve for the width.
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QuestionHow do I find side lengths of a rectangle if only area and perimeter are given?DonaganTop AnswererLet l and w be the length and width respectively. Set up equations in l and w for the perimeter and the area. Use either equation to solve for l in terms of w, or vice versa, then substitute that value of l into the other equation. That will give you the value of w. Use it in either equation to find the value of l.
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QuestionOne side of a square chessboard is 75 cm; how would I find the area of the board?DonaganTop AnswererSquare the side.
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QuestionIf only area is given, how do I find length and height?DonaganTop AnswererYou cannot find length and width if all you're given is area.
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QuestionIf I am given the area and width, how do I get the length?DonaganTop AnswererDivide area by width.
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QuestionHow do I find the length of a rectangle if only the width and the area are given?Community AnswerUse the formula for area for a rectangle. Area = length x width. Plug in your numbers. Let's say you were given 8 for the area and 2 for the width. 8 = 2 x L (L is length). Divide by 2 on each side to get L by itself. 8 ÷ 2 = 4. Now you have 4 = L. 4 would be your length.
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QuestionHow do I find length and width of a rectangle if I know the area and perimeter?DonaganTop AnswererLet x be the length and y the width. Then the area A = xy, and the perimeter P = 2x + 2y. Supply the values for A and P. Then let x = A/y. Substitute "A/y" (using the A value) for "x" in the equation for P (using the P value). Solve for y, then substitute that value back into the equation for A, which will allow you to evaluate x.
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QuestionHow do I find the perimeter when I am only given the length?DonaganTop AnswererTo find the perimeter you would also have to know the width or the area.
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QuestionHow do I find the length and the width of a rectangle when the perimeter is given?DonaganTop AnswererIf all you know is the perimeter, you don't have enough information to find the length or the width.
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QuestionArea of a rectangle in square feet is x^2 + 13x + 36. How much longer is the length than the width of the rectangle?DonaganTop Answererx² + 13x + 36 can be factored into (x + 9)(x + 4). That means that the length and width can be denoted as (x + 9) and (x + 4) respectively. (x + 9) is 5 units longer than (x + 4).
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QuestionHow do I find the breadth of rectangle if I'm only given its length?Community AnswerYou can't find the breadth. To do this, you would also need the area of the rectangle.
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QuestionWhat is the perimeter of a rectangle 45 meters long and 336 meters wide?Top AnswererPerimeter equals 2 × length + 2 × width. 2 × 45 = 90, and 2 × 336 = 672. Adding these two gives you 762 meters.
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QuestionHow do I find length of a rectangle if the perimeter and width are given?Top AnswererMultiply the width by 2 and subtract this result from the perimeter. Then, divide that number by 2 to get the length.
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QuestionCan I find the breadth of a rectangle if I know the length and perimeter?DonaganTop AnswererYes. Divide the perimeter by 2. Subtract the length. That's the breadth/width.
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QuestionThe length and width of one rectangle are each three times the length of another rectangle. Is the area of the first rectangle three times the area of the other triangle?DonaganTop AnswererNo. If the length and width of the first rectangle are each three times the length and width, respectively, of the second rectangle, the first rectangle's area is nine times the second rectangle's area.
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QuestionHow do I find the length and width of rectangle if I only know the area?DonaganTop AnswererIt can't be done. A given area could correspond to several different length/width combinations.
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QuestionThe perimeter of a rectangle is 258 and the width is half of its length. How do I find the width?DonaganTop AnswererThe perimeter is twice the length plus twice the width. Since the width is half the length, the perimeter is two lengths plus two half-lengths, or a total of three lengths. So divide the perimeter by three to get the length: 258 / 3 = 86. That's the length. The width is half the length, or 43. Check by adding 86 + 86 + 43 + 43 = 258.
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QuestionThe perimeter of a volleyball court is 60 m. It is 19 m long. How do I find its width?DonaganTop AnswererThe perimeter is twice the length plus twice the width. Subtract twice the length (38) from the perimeter to get twice the width: 60 - 38 = 22. So the width is 11 meters.
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QuestionHow do I find the width and length of a rectangle if I know the area and the width is 1/3 of its length?DonaganTop AnswererThe area (A) is the width (w) multiplied by the length. The length in this case is three times the width (3w). So A = (w)(3w) = 3w². Then w² = A/3, and w = √(a/3). That's the width. The length is 3√(A/3).
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QuestionWhat if it says the length is 6 times longer than its width?DonaganTop AnswererIf the length of a rectangle is 6 times its width, find its area by multiplying the width by six times the width. That's six times the square of the width. A = (w)(6w) = 6w².
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QuestionHow do I find the length and width of a square if I only know the area?DonaganTop AnswererEach side of a square is equal to the positive square root of its area.
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QuestionHow do I find the length of a rectangle if I know the width?DonaganTop AnswererIf all you know is the width, you can't find the length. You would also have to know the area or the perimeter.
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QuestionA field is in the shape of a rectangle. The perimeter of the field is 300 meters. The length of the field is twice its width. What is the area of the field?DonaganTop AnswererLet x = width. Then 2x = length. 2(x) + 2(2x) = 6x = 300. x = 50. The width is 50 meters. The length is 100 meters. The area is 50 x 100 = 5,000 square meters.
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QuestionHow do I find the area of a rectangle when the length is twice as much as the width?Community AnswerYou do length times width, it does not matter how long the length is. If you are trying to find what the width is to then solve for the area, you already know the length, so you divide it by 2, because the length was twice as long as the width. Then you divide that again by 2 because there are 2 widths. Pick one of the width sides and one length side and multiply them together for the area.
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