Q&A for How to Find the Perimeter of a Rhombus

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What is the perimeter and area of a rhombus with diagonals of 24 cm and 7 cm?

Community Answer

To find the perimeter, follow the steps described in method 2, where you use the lengths of the diagonals to set up the Pythagorean Theorem. 1/2 of 24 = 12; 1/2 of 7 = 3.5. So: 12^2 + 3.5^2 = c^2 144 + 12.25 = c^2 156.25 = c^2 12.5 = c, or the length of one side of the rhombus (S) P = 4S P = 4(12.5) P= 50 cm To find the area, you can read the article "Calculate the Area of a Rhombus." (http://www.wikihow.com/Calculate-the-Area-of-a-Rhombus)

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What if the sides are not equal?

Community Answer

If the sides of the shape are not equal, then the figure is not a rhombus. You can still find the perimeter of any shape by adding up the length of all its sides.

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Question

How do I find the perimeter of a rhombus whose area is 60 cm2 and has a diagonal of 15 cm?

Donagan

Top Answerer

The area (60) is half the product of the diagonals. If d is the unknown diagonal, then 60 = 15d / 2. So 15d = 120, and d = 8 cm. The diagonals of a rhombus are perpendicular to and bisect each other, forming four right triangles, each with legs of 7.5 cm and 4 cm (half each diagonal). By the Pythagorean theorem, we find that each of the sides of the rhombus is √([7.5)² + (4)²] = √[56.25 + 16] = √72.25 = 8.5 cm. The perimeter of the rhombus is four times the length of one side: 34 cm.

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If a rhombus diagonal is 42 cm and 25 cm, how do I find area or perimeter?

Donagan

Top Answerer

The area is half the product of the diagonals. The perimeter is found as shown in Method 2 above.

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