Q&A for How to Find the Width of a Rectangle

You divide the volume by the height and the length. You could multiply the height and the length with each other first before dividing. W = V / (H*L).

Let B equal the breadth. Then 2B equals the length. Write an equation in B, stating that the perimeter is equal to twice the breadth plus twice the length. Solve for B.

Double the width, and subtract that from the perimeter. Then divide that number by two, which gives you the length of the rectangle. Then, multiply the result by the width to get the area.

The length (l) is twice the width (w), so l = 2w. The perimeter, or twice the length plus twice the width, is 33, so 2(2w) + 2w = 33. That means 6w = 33; w = 5½, and 2w = l = 11.

Let x and y be the dimensions of the rectangle. Then xy = 40, and 2x + 2y = 28. From the first equation, x = 40/y. Substituting that value of x into the second equation, 2(40/y) + 2y = (80/y) + 2y = 28. Multiply both sides of this equation by y to get rid of the denominator: 80 + 2y² = 28y. Divide by 2 to simplify: 40 + y² = 14y. Subtract 14y from both sides to get zero on one side, and re-arrange slightly: y² - 14y + 40 = 0. Factor the left side: (y - 10)(y - 4) = 0. Set each factor equal to zero to solve for y: y = 4, 10. That means that one side of the rectangle is 4 inches in length, and the other side is 10 inches.

Set up an equation in which the width (w) is multiplied by four-more-than-the-width (w + 4) to equal 77. Then solve for the width.

Let l and w be the length and width respectively. Set up equations in l and w for the perimeter and the area. Use either equation to solve for l in terms of w, or vice versa, then substitute that value of l into the other equation. That will give you the value of w. Use it in either equation to find the value of l.

Square the side.

You cannot find length and width if all you're given is area.

Divide area by width.

Use the formula for area for a rectangle. Area = length x width. Plug in your numbers. Let's say you were given 8 for the area and 2 for the width. 8 = 2 x L (L is length). Divide by 2 on each side to get L by itself. 8 ÷ 2 = 4. Now you have 4 = L. 4 would be your length.

Let x be the length and y the width. Then the area A = xy, and the perimeter P = 2x + 2y. Supply the values for A and P. Then let x = A/y. Substitute "A/y" (using the A value) for "x" in the equation for P (using the P value). Solve for y, then substitute that value back into the equation for A, which will allow you to evaluate x.

To find the perimeter you would also have to know the width or the area.

If all you know is the perimeter, you don't have enough information to find the length or the width.

x² + 13x + 36 can be factored into (x + 9)(x + 4). That means that the length and width can be denoted as (x + 9) and (x + 4) respectively. (x + 9) is 5 units longer than (x + 4).

You can't find the breadth. To do this, you would also need the area of the rectangle.

Perimeter equals 2 × length + 2 × width. 2 × 45 = 90, and 2 × 336 = 672. Adding these two gives you 762 meters.

Multiply the width by 2 and subtract this result from the perimeter. Then, divide that number by 2 to get the length.

Yes. Divide the perimeter by 2. Subtract the length. That's the breadth/width.

No. If the length and width of the first rectangle are each three times the length and width, respectively, of the second rectangle, the first rectangle's area is nine times the second rectangle's area.

It can't be done. A given area could correspond to several different length/width combinations.

The perimeter is twice the length plus twice the width. Since the width is half the length, the perimeter is two lengths plus two half-lengths, or a total of three lengths. So divide the perimeter by three to get the length: 258 / 3 = 86. That's the length. The width is half the length, or 43. Check by adding 86 + 86 + 43 + 43 = 258.

The perimeter is twice the length plus twice the width. Subtract twice the length (38) from the perimeter to get twice the width: 60 - 38 = 22. So the width is 11 meters.

The area (A) is the width (w) multiplied by the length. The length in this case is three times the width (3w). So A = (w)(3w) = 3w². Then w² = A/3, and w = √(a/3). That's the width. The length is 3√(A/3).

If the length of a rectangle is 6 times its width, find its area by multiplying the width by six times the width. That's six times the square of the width. A = (w)(6w) = 6w².

Each side of a square is equal to the positive square root of its area.

If all you know is the width, you can't find the length. You would also have to know the area or the perimeter.

Let x = width. Then 2x = length. 2(x) + 2(2x) = 6x = 300. x = 50. The width is 50 meters. The length is 100 meters. The area is 50 x 100 = 5,000 square meters.

You do length times width, it does not matter how long the length is. If you are trying to find what the width is to then solve for the area, you already know the length, so you divide it by 2, because the length was twice as long as the width. Then you divide that again by 2 because there are 2 widths. Pick one of the width sides and one length side and multiply them together for the area.