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QuestionWhen do we have deceleration?Benjamin WalkerCommunity AnswerAs the object loses energy passing through a medium. The medium an object is passing through will determine the deceleration.
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QuestionHow do I calculate the velocity of something given its time traveled and distance covered?Community AnswerDivide distance traveled by the time taken to get the average speed. Velocity is the term used for speed when the object travels in a uniform direction (i.e. straight line or circle).
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QuestionHow does velocity change if the distance decreases and the time increases?Community AnswerVelocity decreases. Think about it: It takes a longer time to cover a shorter distance.
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QuestionWhat is the formula for velocity if you aren't given time?Community AnswerVelocity squared=(initial velocity squared) + 2 × ( acceleration due to gravity) × ( distance covered) V×V=u×u + 2as.
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QuestionA stone is thrown with an initial velocity of 15 m/s. How do I find the velocity at t=35?Community AnswerTo find the velocity, use the equation: Final velocity = initial velocity + (acceleration due to gravity)(time).
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QuestionHow can I solve a problem to find initial speed?Community AnswerRe-arrange the equation so that Vi (Initial speed) is isolated. Once isolated, just plug in the numbers and solve.
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QuestionIf an elevator travels 16 meter down in 25 seconds, and than travels 32 meters up in 50 seconds, what is the average speed per meter?Community AnswerYou have to calculate both averages, and then get the mean between the two (though in this instance, both are the same). 1: 16/25 = 0.64 m/s first speed 2: 32/50 = 0.64 m/s second speed 3: (0.64+0.64)/2 = 0.64 average
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QuestionHow do I prove that speed is directly proportional to distance?Community Answervelocity = distance/time. As the distance increases, the velocity also increases.
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QuestionHow do I find the time from velocity?Community AnswerYou need the distance first; the distance divided by the velocity is the time.
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QuestionA body falls from rest with an acceleration of 10m/s^2. What is the going velocity after 5s? How far has it fallen by then?CabbacheCommunity Answer10m/s^2 means that the velocity of the body increases by 10m/s every second. If that happens for 5 seconds, then the velocity at that time would be 10 x 5 = 50m/s. Use the equation s = at^2/2 to find how much it has fallen. S = 10x5^2/2 = 125 meters.
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QuestionIf a cricket ball is thrown vertically upwards with an initial velocity of 40m/s, what is the maximum height attained and the time taken to reach it?CabbacheCommunity AnswerThe velocity will start to decrease from 40 to 0 at a rate of 9.81m/s^2, so it will take 40/9.81 = 4.07 seconds for the ball to reach maximum height and start going back down. You can use the formula s = at^2 / 2 to find the height reached, because now we know the time. 9.81 x 4.07 x 4.07 / 2 = 81.2 meters high.
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QuestionOlga is riding an amusement park ride that launches her upward from rest to a velocity of 19.3 m/s in 3.4 seconds. If her mass is 73.1, what is the normal force of the ride launching her upward?CabbacheCommunity AnswerF = ma. We know m = 73.1Kg so we need to find the acceleration. If the velocity is increased by 19.3 in 3.4 seconds, then every second, it is increased by 19.3/3.4 m/s, so the acceleration is 5.67m/s. Therefore, F = 73.1 x 5.67 = 414.95N.
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