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Q&A for How to Find the Magnitude of a Vector
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QuestionThe coordinates of head and tail of a vector are (2, 1, 0), (-4, 2, -3). What is the magnitude of the vector?Community AnswerYou can use the same formula: |→a| = √((x2 – x1)^2 + (y2 – y1)^2), but add on (z2 – z1)^2 at the end for the third set of coordinates!
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QuestionHow do I find the direction?Community AnswerUse this formula: tan(y component / x component). If the vector is in quadrant 3 or 4, add a half rotation.
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QuestionWhat is the magnitude of the resultant vector of vector A-12.66 and vector B-11.93?Community AnswerTo get the magnitude you need to square both the vectors' magnitude and then take the underroot.
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QuestionHow do I find the magnitude of a vertical and horizontal component if a vector is shown in a scale diagram?Community AnswerIf you're given an angle, use that angle and the vector's magnitude to calculate. Vx= (vector's mag)*cos(angle), Vy= (vector's mag)*sin(angle).
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QuestionHow can I find the magnitude of vectors if there is no coordinates, an angle, and then a force?Community AnswerIf you are given a value for work, you can divide that value by the magnitude of the force multiplied by the cosine of the angle, since W=|F||d|cos⍺ (|d|=W/(|F|cos⍺)).
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QuestionHow do I find the vector when only its modulus is given?Community AnswerOne modulus can apply to more than one vector, so any coordinates that fit the formula |a|= square root of (x^2 = y^2) should work, where |a|= the magnitude/modulus.
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QuestionHow do I find the angle between two vectors?Top Answerer
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QuestionHow do I find the magnitude of vector AB when A is at (-4,-6) and B is at (1,-3)?Top AnswererSubtract 1 from -4 to get -5 and square it to get 25. Subtract -3 from -6 to get -3 and square it to get 9. Add 25 and 9 to get 34. The square root of 34 is approximately 5.83, which is the magnitude of vector AB.
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QuestionWhat is the magnitude of the resultant vector if a person walks 600 meters east, then turns 400 meters north, and finally walks 300 meters west?Top AnswererThe person ends up 400 meters north of the starting point and 300 meters east. The magnitude of the resultant vector is calculated as √[(400)² + (300)²] = √250,000 = 500 meters.
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