Q&A for How to Calculate Multiple Dice Probabilities

Together any two numbers represent one-third of the possible rolls. One-third of 60 is 20, so that's how many times either a 3 or a 6 might be expected to come up in 60 rolls.

Seventeen can be rolled 3 ways - 5,6,6, 6,5,6, and 6,6,5. There are 6^3=216 ways to roll 3 dice, and 3/216 = 1/72. Therefore, the odds of rolling 17 with 3 dice is 1 in 72.

That isn't possible, and therefore there is a zero in one hundred chance.

126/7776. This is if you are using the standard 6 sided die.

On a normal 6-sided die, the odds of either number appearing is 1/6. The odds of the result being one of the two numbers is 2*1/6 = 2/6 = 1/3.

The odds are 1 in 6^10.

A die has 6 faces, so the probability of throwing any specific number is 1 in 6.

Each die has a 50% chance of showing a 4, 5 or 6 on any roll. That means that each die will on average show a 4 or more half the time. The same is true of each die, so when rolling any number of dice, an average of half of them will show 4 or more.

If the dice has 6 sides, then 100%. What number more than 6 could you get? Unless you're using a Magic The Gathering die.

Using the spreadsheet method you get 735 combinations of 16 with 5 dice with 6 sides. Since possible combinations equals 6^5=7776, answer is 735/7776=0.094521.

On each roll there are 11 possible outcomes of this situation out of 36 possible. (1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (3,1) (4,1) (5,1) (6,1). That means ~ 30% chance each roll. (0.3055) probability.

Assuming 6-sided dice, (i) 1/18 (ii) 1/6. To explain: Using enumeration, we quickly see that the only ways to roll a 3 are 1,2 & 2,1 That's 2 results out of 6x6 possibilities, or 2/36 which equals 1/18. By the same method, we find their are 6 ways to roll 7, (1,6 2,5 ... 6,1). 6/36 is 1/6.