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Q&A for How to Solve Exponential Equations
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QuestionWhat do I do with the exponents when the bases are the same?David Jia is an Academic Tutor and the Founder of LA Math Tutoring, a private tutoring company based in Los Angeles, California. With over 10 years of teaching experience, David works with students of all ages and grades in various subjects, as well as college admissions counseling and test preparation for the SAT, ACT, ISEE, and more. After attaining a perfect 800 math score and a 690 English score on the SAT, David was awarded the Dickinson Scholarship from the University of Miami, where he graduated with a Bachelor’s degree in Business Administration. Additionally, David has worked as an instructor for online videos for textbook companies such as Larson Texts, Big Ideas Learning, and Big Ideas Math.Whenever you're solving exponents and the bases are the same, you can add the exponents together. If you have x^2 times x^3, you would add the exponents together and get x^5.
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QuestionHow do I calculate 1.025 base number (exponent) to power 12 easily?DonaganTop AnswererManually, there is no easy way to do this. The only easy way is to use a calculator with an exponent function (often shown by the symbol "^").
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QuestionI made a formula -1+2^n=X to find the maximum number countable with so many digits in binary. How do I turn it around to find the number of digits for a certain number? I want to input x to find n.Community AnswerOK, you can rearrange to have 2^n = X+1. Then take logs of both sides. log (2^n) = log (X+1). Then you can use properties of logs to get n*log2 = log(X+1) and solve for n = log(x+1)/log2. That's not quite what you want because you need the formula to return whole numbers for n, but you can fix that by saying n = ceil(log(X+1)/log2) where ceil is the rounding up function. Everything here works no matter what base you do the logarithms in (as long as you use the same base for them all), but do them in base 2 if you can because then the formula reduces to n = ceil(log_2 (X+1)).
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QuestionHow do I solve 2^5/2 - 2^3/2?DonaganTop Answerer2^5/2 is √(2^5), or √32 = 5.66. 2^3/2 is √(2³), or √8 = 2.83. 5.66 - 2.83 = 2.83.
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QuestionWhat is of a¾ = 81?DonaganTop AnswererTo solve for "a," raise 81 to the power of 4/3. That is, raise 81 to the fourth power, then find the cube root of that number. 81^4 = 43,046,721. The cube root of 43,046,721 = 350.467. That's "a."
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QuestionI still can't understand how x-4=5 could be made into x=5+4? It's confusing me a lot.VerinTop AnswererAll that's happening is that 4 is being added to both sides of the equation. On the left side, we x - 4 + 4, which equals x, and on the right side, we get 5 + 4, which equals 9. Thus, the full equation becomes x - 4 (+ 4) = 5 (+4), which simplifies to x = 9. The 4 must be added to both side to maintain the equality.
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QuestionHow can I solve 4(4^x – 2^x) + 1 = 2^x?Community AnswerDistribute the 4 then take the natural log of both sides and isolate the x to get your answer.
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