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Find the derivative with or without an equation

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Estimate the derivative at a point by drawing a tangent line and calculating its slope. If you have the function, you can find the equation for a derivative by using the formal definition of a derivative. This wikiHow guide will show you how to estimate or find the derivative from a graph and get the equation for the tangent slope at a specific point.

Things You Should Know

  • To estimate the tangent slope at a point, draw a tangent line at the point. Then, choose two points on the tangent line.
  • Use the formula slope = (y2 - y1) / (x2 - x1) to find the tangent slope.
  • To find the derivative, use the equation f’(x) = [f(x + dx) – f(x)] / dx, replacing f(x + dx) and f(x) with your given function.
  • Simplify the equation and solve for dx→0. Replace dx in the equation with 0. This will give you the final derivative equation.
Method 1
Method 1 of 3:

Estimate without an Equation

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  1. Use a straightedge to draw a tangent line at the point on the graph that you want to estimate the derivative for. The derivative describes how the slope of a curve changes as x, the horizontal value, changes. Drawing a tangent line allows you to estimate the derivative (the tangent slope) at a given point. [1]
    • A tangent line is a straight line that touches a curve at a single point.
    • The tangent slope is the slope of the tangent line.
    • Make sure your curve and tangent line are drawn on a graph with grid lines. This will make it easier to calculate the tangent slope.
    • Since this is a hand-drawn method, this calculation will only be an estimate, not the exact derivative at a point.
  2. Choose two points that the tangent line passes through. Use the grid to find two simple points, preferably integers. The equation to find the slope with two points is. [2]
    • slope = (y2 - y1) / (x2 - x1)
    • using the points (x1, y1) and (x2, y2)
      • for example, if you have the points (1, 3) and (3, 7),
      • slope = (7 - 3) / (3 - 1)
      • slope = 4 / 2
      • slope = 2
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Method 2
Method 2 of 3:

Finding the Derivative Equation

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  1. The derivative can be defined as the equation: [3]
    • (df / dx)(x) = [f(x + dx) – f(x)] / dx
    • which can be written as f’(x) = [f(x + dx) – f(x)] / dx
    • where
      • f(x) is the function f of x (sometimes written as “y”), i.e. how the value of y changes as the value of x changes
      • f’(x) is the derivative of f(x), as indicated by the prime symbol (’)
      • dx is a small change in x that approaches 0
      • f(x + dx) is the value of y at the horizontal value x + dx
  2. This will be f(x), the function for the curve on the graph. [4] For example, f(x) = x^2.
    • For more general calculus tips, see our guide on how to do well in calculus.
    • If you’re looking for how to use derivative rules, check out How to Differentiate Polynomials .
  3. Replace the terms f(x + dx) and f(x) with your given function. For example, if you were given f(x) = x^2, you would write the formal definition as:
    • f’(x) = [(x + dx)^2 – (x)^2] / dx
  4. For simple functions, you can simplify the function algebraically. [5] Here’s a step by step example for f’(x) = [(x + dx)^2 – (x)^2] / dx
    • Our starting equation:
      • f’(x) = [(x + dx)^2 – (x)^2] / dx
    • Writing out the expanded polynomial term:
      • f’(x) = [x^2 + 2xdx + dx^2 – x^2] / dx
    • The terms x^2 and – x^2 equal zero, resulting in:
      • f’(x) = [2xdx + dx^2] / dx
    • Both terms in the numerator have a dx, which can cancel out with the dx in the denominator, giving the simplified equation:
      • f’(x) = 2x + dx
  5. Replace every instance of dx with a 0. For our example, this would yield the equation:
    • f’(x) = 2x + 0
    • which simplifies to:
      • f’(x) = 2x
    • So, the derivative of f(x) = x^2 is f’(x) = 2x
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Method 3
Method 3 of 3:

Finding the Tangent Slope at a Single Point

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  1. Follow the previous method, Finding the Derivative Equation, to get the derivative equation for the given function f(x).
  2. Replace x in the derivative function f’(x). Using our previous example:
    • Find the slope of the tangent line at x = 5 for the function f(x) = x^2.
      • f’(x) = 2x
      • f’(5) = 2(5)
      • f’(5) = 10
    • The slope of the tangent line at x = 5 is 10.
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  • Question
    f(x) = 4x² -x +2 at x =0
    I_l1ke_gam3s
    Community Answer
    The derivative of this is 8x - 1. The derivative when x = 0 is 8(0) - 1 = -1.
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