Q&A for How to Find the Area and Perimeter of a Rectangle

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Can I find the perimeter of a rectangle with an area of 50?

Donagan

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No. Various combinations of length and width could form an area of 50, and therefore the perimeter could be various sizes. For example, if the rectangle measured 5 x 10, the area would be 50, and the perimeter would be 30. If the rectangle measured 2 x 25, the area would be 50, and the perimeter would be 54.

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How can I make something 9 feet long with an area of 72 feet?

Danoyachtcapt

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A rectangle measuring 9 feet by 8 feet would have an area of 72 square feet.

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A boy runs around a rectangular ground. Its length is thrice its breadth. If the boy covers 2 km in 5 rounds, what is the length of the ground?

Donagan

Top Answerer

The length (l) equals three times the width (w), so that l = 3w. The perimeter is twice the length plus twice the width, or 2 l + 2 w, which is 2(3w) + 2 w, so that the perimeter equals 8 w. We're told that five perimeters equals 2 km, so that 5(8w) = 40w = 2 km. That means that w = 1/20 km. That means that l = 3(1/20 km) = 3/20 km.

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How do I find perimeter when the area and length are given?

Donagan

Top Answerer

Divide the area by the length to get the width. To get the perimeter, add twice the width and twice the length.

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Mary is making a quilt from square pieces of cloth. She fit 10 pieces along one side and 15 pieces along the other. How many pieces does she need?

Donagan

Top Answerer

Assuming that the lengths each consist of 15 squares, and the widths each consist of 10 additional squares (with no corner squares being counted twice, i.e., as part of both the length and the width), it would require 12 x 15 = 180 squares. If you do count the corner squares twice, it would require 8 x 15 = 120 squares.

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If the area and perimeter are given, how can I get the length and width of a rectangle?

Donagan

Top Answerer

Set up two equations in two unknowns. Let l be the length and w the width. Then write the equation for area in l and w. Then write the equation for perimeter in l and w. Then solve the equations simultaneously.

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Do all rectangles with an area of 24 units squared have the same perimeter?

Donagan

Top Answerer

No. For example, a rectangle measuring 4 x 6 would have a perimeter of 20, but a rectangle measuring 3 x 8 would have a perimeter of 22.

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How do I find the perimeter when length is twice the breadth?

Donagan

Top Answerer

The perimeter is twice the width plus twice the length: 2w + 2l. When the length is twice the width (l = 2w), the perimeter is 2(l) + 2 (w) = 2(2w) + 2 (w) = 4w + 2w = 6w.

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If I have an irregularly-shaped area, how can I calculate the area by measuring the perimeter only?

Donagan

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That cannot be done.

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length is 12 width is 5.5+x what is the area?

Community Answer

Area = length times width: A = (12)(5.5 + x) = (66 + 12x) square units.

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The area of a rectangle is 1500 sq ft. The length is 20 feet longer than the width. How do I find the length and width?

Community Answer

Let x be the width. Then (x + 20) is the length. 1500 = (x)(x + 20) = x² + 20x. So 1500 = x² + 20x. Now subtract 1500 from both sides of that last equation: 0 = x² + 20x - 1500 = (x + 50)(x - 30) = 0. That means that x = -50 or +30. Since the width can't be a negative number, we reject the -50 solution, and x = 30 feet. That makes the length of the rectangle (30 + 20) or 50 feet. So the width is 30, the length is 50, and the area is (30)(50) = 1500 sq ft.

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A rectangle has a perimeter of 200 ft. The length is 3 times the width. How do you find the length and width?

Community Answer

Let x be the width. Then 3x is the length. The perimeter is twice the width (2x) plus twice the length (6x). So the perimeter is 2x + 6x = 8x = 200, and x = 25 ft. That's the width. The length is three times that, or 75 ft. To check the answer, 2(25) + 2(75) = 50 + 150 = 200.

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