How to Calculate Joules

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Named for English physicist James Prescott Joule, the joule (J) is one of the cornerstone units of the International metric system. The joule is used as a unit of work, energy, and heat, and is widely used in scientific applications. If you want your answer to be in joules, always make sure to use standard scientific units. The "foot pound" or the "British thermal unit" are still used in some fields, but they have no place in your physics homework.

Formulas

Joules are a unit of energy. Here are formulas for the most common situations where you would calculate energy. As long as you use the SI units listed beneath each formula, your answer will be in joules.

    • →
    • →
    • →
    • → joules = grams * c * ΔT
    • T = temperature in terms of ºC or kelvins
    • Specific heat capacity c depends on the material being heated. Its units are joules / gramsºC .
    • →
Method 1
Method 1 of 5:

Calculating Work in Joules

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  1. If you push a box across the room, you've done work. If you lift it upward, you've done work. There are two important qualities that have to be there for "work" to happen: [1]
    • You're applying constant force.
    • The force is causing the object to move in the direction of the force.
  2. Work is easy to calculate . Just multiply the amount of force used, and the amount of distance traveled. Usually, scientists measure force in Newtons, and distance in meters. If you use these units, your answer will be work in units of Joules. [2]
    • Whenever you read a word problem about work, stop and think where the force is being applied. If you lift a box, you're pushing upward, and the box is moving up — so the distance is however much it rises. But if you then walk forward holding the box, there's no work happening at all. You're pushing upward still, to keep the box from falling, but the box isn't moving up. [3]
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  3. Find the mass of the object being moved. You need to know the mass to figure out how much force you need to move it. For our first example, we'll use a person lifting a weight from the floor to her chest, and calculate how much work that person exerts on the weight. Let's say the weight has a mass of 10 kilograms (kg). [4]
    • Avoid using pounds or other non-standard units, or your final answer won't be in terms of joules.
  4. Calculate the force . Force = mass x acceleration. [5] In our example, lifting a weight straight up, the acceleration we're fighting is due to gravity, which equals 9.8 meters/second 2 . Calculate the force required to move our weight upward by multiplying (10 kg) x (9.8 m/s 2 ) = 98 kg m/s 2 = 98 Newtons (N).<
    • If the object is being moved horizontally, gravity is irrelevant. The problem may ask you to calculate the force required to overcome friction instead. If the problem tells you how fast the object is accelerating when it is pushed, you can multiply the acceleration given with the mass.
  5. For this example, let's say the weight is being lifted 1.5 meters (m). The distance must be measured in meters, or your final answer will not be written in Joules. [6]
  6. To lift a 98 Newton weight 1.5 meters upward, you'll need to exert 98 x 1.5 = 147 Joules of work. [7]
  7. Our example above was simple: someone exerted a force upward on the object, and the object moved upward. Sometimes, the direction of the force and the movement of the object aren't quite the same, due to multiple forces acting on the object. In the next example, we'll calculate the amount of Joules needed for a kid to drag a sled 20 meters across flat snow by pulling on a rope angled upward at 30º. For this scenario, Work = force x cosine(θ) x distance. The θ symbol is the Greek letter "theta," and describes the angle between the direction of force and the direction of movement. [8]
  8. For this problem, let's say the kid is pulling on the rope with a force of 10 Newtons. [9]
    • If the problem gives you the "rightward force," "upward force," or "force in the direction of motion," it has already calculated the "force x cos(θ)" part of the problem, and you can skip down to multiplying the values together
  9. Only some of the force is pulling the sled forward. Since the rope is at an angle upward, the rest of the force is trying to yank the sled upward, uselessly pulling against gravity. Calculate the force that applies in the direction of motion: [10]
    • In our example, the angle θ between the flat snow and the rope is 30º.
    • Calculate cos(θ). cos(30º) = (√3)/2 = about 0.866. You can use a calculator to find this value, but make sure your calculator is set to the same unit as your angle measurement (degrees or radians).
    • Multiply the total force x cos(θ). In our example, 10N x 0.866 = 8.66 N of force in the direction of motion.
  10. Now that we know how much force is actually going toward the direction of motion, we can calculate work as usual. Our problem tells us the sled moved 20 meters forward, so calculate 8.66 N x 20 m = 173.2 joules of work. [11]
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Method 2
Method 2 of 5:

Calculating Joules from Watts

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  1. Watts are a measure of power , or how fast energy is used (energy over time). Joules is a measure of energy . In order to convert from watts to joules, you need to specify a length of time. [12] The longer a current flows, the more energy it uses.
  2. A 1 Watt device consumes 1 Joule of energy every 1 second. If you multiply the number of watts by the number of seconds, you'll end up with joules. To find out how much energy a 60W light bulb consumes in 120 seconds, simply multiply (60 watts) x (120 seconds) = 7200 Joules. [13]
    • This formula works for any form of power measured in watts, but electricity is the most common application.
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Method 3
Method 3 of 5:

Calculating Kinetic Energy in Joules

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  1. Kinetic energy is the amount of energy in the form of motion. Like any unit of energy, it can be express in units of Joules. [14]
    • Kinetic energy is equivalent to the amount of work done to accelerate a stationary object to a certain speed. Once it has reached that speed, the object retains that amount of kinetic energy until that energy transforms into heat (from friction), gravitational potential energy (from moving against gravity), or other types of energy.
  2. For example, we can measure the kinetic energy of a bicycle & bicyclist. Let's say the cyclist has a mass of 50 kg, and the cycle has a mass of 20 kg, for a total mass m of 70 kg. We can now treat them as one 70 kg object, since they'll be traveling together at the same speed. [15]
  3. Calculate speed . If you already know the bicyclist's speed or velocity, just write it down and move on. If you need to calculate it yourself, use one of these methods below. Note that we care about the speed, not the velocity (which is speed in a certain direction), even though the abbreviation v is often used. Ignore any turns the bicyclist makes and pretend all distance traveled is one straight line. [16]
    • If the bicyclist moved at a constant rate (didn't accelerate), measure the distance the bicyclist traveled in meters, and divide it by the number of seconds it took to move that distance. This will give you the average speed, which in this scenario is the same as the speed at any given moment.
    • If the bicyclist is accelerating at constant acceleration and doesn't change direction, calculate his speed at time t with the formula "speed at time t = (acceleration)( t ) + initial speed. Use seconds to measure time, meters/second to measure speed, and m/s 2 to measure acceleration.
  4. Kinetic energy = (1/2)mv 2 . [17] For instance, if the bicyclist is traveling at 15 m/s, its kinetic energy K = (1/2)(70 kg)(15 m/s) 2 = (1/2)(70 kg)(15 m/s)(15 m/s) = 7875 kgm 2 /s 2 = 7875 newton meters = 7875 joules.
    • The kinetic energy formula can be derived from the definition of work, W = FΔs, and the kinematic equation v 2 = v 0 2 + 2aΔs. [18] Δs refers to "change in position," or the amount of distance traveled.
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Method 4
Method 4 of 5:

Calculating Heat in Joules

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  1. Use a balance or spring scale for this. If the object is a liquid, first weigh the empty container the liquid will be held in and find its mass. You'll need to subtract this from the mass of the container and liquid together to find the liquid's mass. For this example, we'll assume the object is 500 grams of water.
    • Use grams, not any other unit, or the result will not be in Joules.
  2. Find the object's specific heat capacity . This information can be found in a chemistry reference, either in book form or online. For water, the specific heat capacity c is 4.19 joules per gram for each degree Celsius it is heated – or 4.1855, if you need to be very precise. [19]
    • Specific heat capacity actually varies slightly based on temperature and pressure. Different organizations and textbooks use different "standard temperatures," so you may see the specific heat capacity of water listed as 4.179 instead.
    • You can use Kelvin instead of Celsius, since a difference in temperature is the same in both units (heating something by 3ºC is the same as heating by 3 Kelvin). Do not use Fahrenheit, or your result will not be in Joules.
  3. If the object is a liquid, you can use a bulb thermometer. For some objects, you may need a probe thermometer.
  4. This will let use measure the amount of heat being added to the object during the heat.
    • If you want to measure the total amount of energy stored as heat, you can pretend the initial temperature was absolute zero: 0 Kelvin or -273.15ºC. This is not typically useful.
  5. This will produce the degrees of temperature change in the object. Assuming the water was originally at 15 degrees Celsius and heated to 35 degrees Celsius, the temperature change would be 20 degrees Celsius. [20]
  6. This formula is written H = mc Δ T , where ΔT means "change in temperature." [21] For this example, this would be 500g x 4.19 x 20, or 41,900 joules.
    • Heat is more commonly expressed in the metric system in terms of either calories or kilocalories. A calorie is defined as the amount of heat required to raise the temperature of 1 gram of water 1 degree Celsius, while a Kilocalorie (or Calorie) is the amount of heat required to raise the temperature of 1 kilogram of water 1 degree Celsius. In the example above, raising 500 grams of water 20 degrees Celsius would expend 10,000 calories or 10 kilocalories.
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Method 5
Method 5 of 5:

Calculating Electrical Energy in Joules

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  1. The steps below are written as a practical example, but you can use the method to understand written physics problems as well. First, we'll calculate the power P using the formula P = I 2 x R, where I is the current in amperes (amps) and R is the resistance in ohms. [22] These units give us the power in watts, so from there, we' can use the formula in the previous step to calculate the energy in joules.
  2. Resistors are rated in ohms, with the rating either labeled directly or indicated with a series of colored bands. You can also test a resistor's resistance by connecting it to an ohmmeter or multimeter . [23] For this example, we'll assume the resistor is rated at 10 ohms.
  3. Either connect wires to the resistor with Fahnestock or alligator clips, or plug the resistor into a testing board.
  4. For this example, we'll use a period of 10 seconds. [24]
  5. Do this with an ammeter or a multimeter. Most household current is in milliamperes, or thousandths of an ampere, so we'll assume the current is 100 milliamperes, or 0.1 ampere.
  6. To find the power, multiply the square of the current by the resistance. This yields the power output in watts. Squaring 0.1 gives 0.01, multiplied by 10, gives a power output of 0.1 watt, or 100 milliwatts. [25]
  7. This gives the energy output in joules. 0.1 watt x 10 seconds equals 1 joule of electrical energy. [26]
    • As joules are small units, and because appliances commonly use watts, milliwatts, and kilowatts to indicate how much power they use, utilities commonly measure their energy output in kilowatt-hours. One watt equals 1 joule per second, or 1 joule equals 1 watt-second; a kilowatt equals 1 kilojoules per second and a kilojoule equals 1 kilowatt-second. As there are 3,600 seconds in an hour, 1 kilowatt-hour equals 3,600 kilowatt-seconds, 3,600 kilojoules, or 3,600,000 joules.
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  • Question
    Hair dryer (1500 W) operated for 5 minutes what's the amount of electrical energy?
    Community Answer
    1500W = 1500 J/s. 5 minutes = 300 s. Amount of Joules = 300 s * 1500 J/s = 450000 J = 450 kJ.
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  • Question
    How do I convert kilojoules into joules?
    Community Answer
    There are 1000 joules per kilojoule. Therefore, multiply the kilojoule value by 1000 to get the joule equivalent value. Example: 4.23 kJ = 4230J.
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      Tips

      • Related to the joule is another metric unit of work and energy called the erg; 1 erg equals 1 dyne of force times a distance of 1 cm. One joule equals 10,000,000 ergs.
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      Warnings

      • Although the terms "joule" and "newton-meter" describe the same unit, in practice "joule" is used when representing any form of energy and for work performed in a straight line, as in the example above of running up a flight of stairs. When used to measure torque, the application of force in rotating an object, the term "newton-meter" is preferred.
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      Things You'll Need

      Work or Kinetic Energy:

      • Stopwatch or timer
      • Scale or balance
      • Calculator with cosine function (work only, not always needed)

      Calculating Electrical Energy:

      • Resistor
      • Wires or test board
      • Multimeter (or separate ohmmeter and ammeter)
      • Fahnestock or alligator clips

      Heat:

      • Object to heat
      • Heat source (such as a Bunsen burner)
      • Thermometer (either bulb or probe thermometer)
      • Chemistry reference book (for finding the specific heat capacity of the object being heated)

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      References

      1. ↑ https://www.physicsclassroom.com/class/energy/Lesson-1/Definition-and-Mathematics-of-Work
      2. ↑ https://www.physicsclassroom.com/class/energy/Lesson-1/Definition-and-Mathematics-of-Work
      3. ↑ https://www.physicsclassroom.com/Class/energy/u5l1a.cfm#waiter
      4. ↑ https://openstax.org/books/physics/pages/9-1-work-power-and-the-work-energy-theorem
      5. ↑ https://openstax.org/books/physics/pages/9-1-work-power-and-the-work-energy-theorem
      6. ↑ https://openstax.org/books/physics/pages/9-1-work-power-and-the-work-energy-theorem
      7. ↑ https://flexbooks.ck12.org/cbook/ck-12-middle-school-physical-science-flexbook-2.0/section/13.2/primary/lesson/calculating-work-ms-ps/
      8. ↑ https://www.physicsclassroom.com/Class/energy/u5l1a.cfm
      9. ↑ https://flexbooks.ck12.org/cbook/ck-12-middle-school-physical-science-flexbook-2.0/section/13.2/primary/lesson/calculating-work-ms-ps/
      1. ↑ https://courses.lumenlearning.com/suny-physics/chapter/19-1-electric-potential-energy-potential-difference/
      2. ↑ https://openstax.org/books/physics/pages/9-1-work-power-and-the-work-energy-theorem
      3. ↑ https://www.rapidtables.com/convert/electric/Watt_to_Joule.html
      4. ↑ https://flexbooks.ck12.org/cbook/ck-12-middle-school-physical-science-flexbook-2.0/section/13.3/primary/lesson/power-ms-ps/
      5. ↑ https://www.physicsclassroom.com/class/energy/u5l1c.cfm
      6. ↑ https://flexbooks.ck12.org/cbook/ck-12-middle-school-physical-science-flexbook-2.0/section/14.2/primary/lesson/kinetic-energy-ms-ps/
      7. ↑ https://www.physicsclassroom.com/class/energy/u5l1c.cfm
      8. ↑ https://www.mathsisfun.com/physics/energy-potential-kinetic.html
      9. ↑ https://physics.info/energy-kinetic/
      10. ↑ https://www.engineeringtoolbox.com/water-thermal-properties-d_162.html
      11. ↑ https://www.omnicalculator.com/physics/specific-heat
      12. ↑ https://www.omnicalculator.com/physics/specific-heat
      13. ↑ https://electronicsclub.info/power.htm
      14. ↑ https://www.allaboutcircuits.com/tools/electrical-energy-calculator/
      15. ↑ https://www.allaboutcircuits.com/tools/electrical-energy-calculator/
      16. ↑ https://www.allaboutcircuits.com/tools/electrical-energy-calculator/
      17. ↑ https://www.allaboutcircuits.com/tools/electrical-energy-calculator/

      About This Article

      Article Summary X

      To calculate heat in joules, start by finding the mass in grams of the object being heated. Then, find the object's heat capacity in Celsius or Kelvin. Once you have the mass and heat capacity, find the object's current temperature and its temperature after it's heated. Next, subtract the original temperature from the heated temperature and multiply the difference by the mass and the heat capacity to find the heat in joules. To learn how to calculate energy or work in joules, keep reading!

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