Introvert or Extrovert Quiz
Q&A for How to Play Old Maid
Coming soon
Search
-
QuestionWhen you set down a pair, does it go to the next player?Community AnswerNope, you don't need to do anything with the pairs besides place them face-up in front of you. They'll sit there until the game is over.
-
QuestionWhen the person I was drawing from runs out of cards, do I draw from the next person?Community AnswerIf the person to your left is out, then you would automatically skip them and the next person to your left is the one you would take from.
-
QuestionWhat if there is a tie on the number of pairs?Community AnswerThe players can either play a one on one rematch, or accept the results as a tie.
-
QuestionWhat do I do if one person has more cards than the other when playing Old Maid?Community AnswerYou can discard a randomly selected card from their hand (unless it's the Old Maid) to even their hand. If you have cards left over, you can deal more to even everything up.
-
QuestionHow is the draw pile used?Community AnswerIt is a pile of cards that players can take from when they don't have any cards in their hand that they can play.
-
QuestionWhat if I run out of cards before the end of the game and I don't have the old maid?Community AnswerYou are out of the game and automatically win. There are multiple winners, but just one loser.
-
QuestionDo I only draw from the person to my left one time, or do I keep going until I get a pair?Community AnswerYou only need to take one card from the person on your left. If it makes a pair, you place those face up on the table. If not, the next person draws from you.
-
QuestionWhat if a person runs out of cards?Community AnswerThen they are out of the game and also a winner. There is only one loser in the game, but multiple winners.
-
QuestionHow old do you have to be to play Old Maid?Undertale4141Top AnswererAs long as a player understands the rules their age doesn’t matter. Old Maid is fairly simple, so a young child (around four or five) should be able to play.
Ask a Question
200 characters left
Include your email address to get a message when this question is answered.
Submit