Download Article
Download Article
Logarithms might be intimidating, but solving a logarithm is much simpler once you realize that logarithms are just another way to write out exponential equations. Once you rewrite the logarithm into a more familiar form, you should be able to solve it as you would solve any standard exponential equation.
Steps
Download Article
Before You Begin: Learn to Express a Logarithmic Equation Exponentially [1] X Research source [2] X Research source
-
Know the logarithm definition. Before you can solve logarithms, you need to understand that a logarithm is essentially another way to write an exponential equation. It's precise definition is as follows:
- y = log b
(x)
- If and only if: b y = x
- Note that b
is the base of the logarithm. It must also be true that:
- b > 0
- b does not equal 1
- In the same equation, y is the exponent and x is the exponential expression that the logarithm is set equal to.
- y = log b
(x)
-
Look at the equation. When looking at the problem equation, identify the base (b), exponent (y), and exponential expression (x).
- Example:
5 = log 4
(1024)
- b = 4
- y = 5
- x = 1024
Advertisement - Example:
5 = log 4
(1024)
-
Move the exponential expression to one side of the equation. Set the value of your exponential expression, x , to one side of the equal sign.
- Example: 1024 = ?
-
Apply the exponent to the base. The value of your base, b , needs to be multiplied by itself by the amount of times indicated by your exponent, y .
- Example:
4 * 4 * 4 * 4 * 4 = ?
- This could also be written as: 4 5
- Example:
4 * 4 * 4 * 4 * 4 = ?
-
Rewrite your final answer. You should be able to rewrite the logarithm as an exponential expression now. Verify that your answer is correct by making sure that both sides of the equation are equal.
- Example: 4 5 = 1024
Advertisement
-
Isolate the logarithm. Use inverse operations to move any part of the equation that is not part of the logarithm to the opposite side of the equation.
- Example:
log 3
( x
+ 5) + 6 = 10
- log 3 ( x + 5) + 6 - 6 = 10 - 6
- log 3 ( x + 5) = 4
- Example:
log 3
( x
+ 5) + 6 = 10
-
Rewrite the equation in exponential form. Using what you now know about the relationship between logarithms and exponential equations, break the logarithm apart and rewrite the equation in a simpler, solvable exponential form.
- Example:
log 3
( x
+ 5) = 4
- Comparing this equation to the definition [ y = log b (x) ], you can conclude that: y = 4; b = 3; x = x + 5
- Rewrite the equation so that: b y = x
- 3 4 = x + 5
- Example:
log 3
( x
+ 5) = 4
-
Solve for x . With the problem simplified into a basic exponential equation, you should be able to solve it as you would solve any exponential equation.
- Example:
3 4
= x + 5
- 3 * 3 * 3 * 3 = x + 5
- 81 = x + 5
- 81 - 5 = x + 5 - 5
- 76 = x
- Example:
3 4
= x + 5
-
Write your final answer. The answer you got when solving for x is the solution to your original logarithm.
- Example: x = 76
Advertisement
Method 2
Method 2 of 3:
Solve for X Using the Logarithmic Product Rule [3] X Research source [4] X Research source
Download Article
-
Know the product rule. The first property of logarithms, known as the "product rule," states that the logarithm of a multiplied product equals the sum of the logarithms of both factors. Written in equation form:
- log b (m * n) = log b (m) + log b (n)
- Also note that the following must be true:
- m > 0
- n > 0
-
Isolate the logarithm to one side of the equation. Use inverse operations to shift the parts of the equation around so that all logarithms are on one side of the equation while all other elements are on the opposite side.
- Example:
log 4
(x + 6) = 2 - log 4
(x)
- log 4 (x + 6) + log 4 (x) = 2 - log 4 (x) + log 4 (x)
- log 4 (x + 6) + log 4 (x) = 2
- Example:
log 4
(x + 6) = 2 - log 4
(x)
-
Apply the product rule. If there are two logarithms added together in the equation, you can use the product rule to combine the two logarithms into one.
- Example:
log 4
(x + 6) + log 4
(x) = 2
- log 4 [(x + 6) * x] = 2
- log 4 (x 2 + 6x) = 2
- Example:
log 4
(x + 6) + log 4
(x) = 2
-
Rewrite the equation in exponential form. Remember that a logarithm is just another way to write an exponential equation. Use the logarithm definition to rewrite the equation in its solvable form.
- Example:
log 4
(x 2
+ 6x) = 2
- Comparing this equation to the definition [ y = log b (x) ], you can conclude that: y = 2; b = 4 ; x = x 2 + 6x
- Rewrite the equation so that: b y = x
- 4 2 = x 2 + 6x
- Example:
log 4
(x 2
+ 6x) = 2
-
Solve for x . Now that the equation has become a standard exponential equation, use your knowledge of exponential equations to solve for x as you usually would.
- Example:
4 2
= x 2
+ 6x
- 4 * 4 = x 2 + 6x
- 16 = x 2 + 6x
- 16 - 16 = x 2 + 6x - 16
- 0 = x 2 + 6x - 16
- 0 = (x - 2) * (x + 8)
- x = 2; x = -8
- Example:
4 2
= x 2
+ 6x
-
Write your answer. At this point, you should have the solution for the equation. Write it down in the space provided for your answer.
- Example: x = 2
- Note that you cannot have a negative solution for a logarithm, so you can discard x - 8 as a solution.
Advertisement
Method 3
Method 3 of 3:
Solve for X Using the Logarithmic Quotient Rule [5] X Research source
Download Article
-
Know the quotient rule. According to the second property of logarithms, known as the "quotient rule," the logarithm of a quotient can be rewritten by subtracting the logarithm of the denominator from the logarithm of the numerator. Written as an equation:
- log b (m / n) = log b (m) - log b (n)
- Also note that the following must be true:
- m > 0
- n > 0
-
Isolate the logarithm to one side of the equation. Before you can solve the logarithm, you need to shift all logs in the equation to one side of the equal sign. The other parts of the equation should all be shifted to the opposite side of the equation. Use inverse operations to accomplish this.
- Example:
log 3
(x + 6) = 2 + log 3
(x - 2)
- log 3 (x + 6) - log 3 (x - 2) = 2 + log 3 (x - 2) - log 3 (x - 2)
- log 3 (x + 6) - log 3 (x - 2) = 2
- Example:
log 3
(x + 6) = 2 + log 3
(x - 2)
-
Apply the quotient rule. If there are two logarithms in the equation and one must be subtracted by the other, you can and should use the quotient rule to combine the two logarithms into one.
- Example:
log 3
(x + 6) - log 3
(x - 2) = 2
- log 3 [(x + 6) / (x - 2)] = 2
- Example:
log 3
(x + 6) - log 3
(x - 2) = 2
-
Rewrite the equation in exponential form. Now that there is only one logarithm in the equation, use the logarithms definition to rewrite the equation in exponential form, thereby removing the log.
- Example:
log 3
[(x + 6) / (x - 2)] = 2
- Comparing this equation to the definition [ y = log b (x) ], you can conclude that: y = 2; b = 3; x = (x + 6) / (x - 2)
- Rewrite the equation so that: b y = x
- 3 2 = (x + 6) / (x - 2)
- Example:
log 3
[(x + 6) / (x - 2)] = 2
-
Solve for x . With the equation now in exponential form, you should be able to solve for x as you usually would.
- Example:
3 2
= (x + 6) / (x - 2)
- 3 * 3 = (x + 6) / (x - 2)
- 9 = (x + 6) / (x - 2)
- 9 * (x - 2) = [(x + 6) / (x - 2)] * (x - 2)
- 9x - 18 = x + 6
- 9x - x - 18 + 18 = x - x + 6 + 18
- 8x = 24
- 8x / 8 = 24 / 8
- x = 3
- Example:
3 2
= (x + 6) / (x - 2)
-
Write your final answer. Go back and double-check your steps. Once you feel certain that you have the correct solution, write it down.
- Example: x = 3
Advertisement
Community Q&A
Search
-
QuestionWhy do we consider positive answers only?Community AnswerLogarithmic graphs have asymptotes at x=0, therefore any negative answers cannot exist.
-
QuestionHow do I find the antilog of 12.18?LinnieTop AnswererUnderstand that the antilog of 12.18 is a common antilogarithm question, which means the assumed subscript is 10. To solve this problem, take 10 to the power of 12.18. This gives you an approximate value of 1,513,561,248,436.21.
-
QuestionHow do you do 4^x+10 = 10?Community Answer4^x + 10 = 10. Subtract 10 from both sides. 4^x = 0. Rewrite according to the definition of a logarithm. log4(0) = x. Use the change of base formula to calculate log4(0). log(0)/log(4) = x log(0) is undefined, making x undefined as well.
Ask a Question
200 characters left
Include your email address to get a message when this question is answered.
Submit
Advertisement
Video
Tips
Submit a Tip
All tip submissions are carefully reviewed before being published
Name
Please provide your name and last initial
Thanks for submitting a tip for review!
References
- ↑ https://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/col_alg_tut43_logfun.htm#logdef
- ↑ https://www.mathsisfun.com/algebra/logarithms.html
- ↑ https://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/col_alg_tut46_logeq.htm
- ↑ https://www.youtube.com/watch?v=fnhFneOz6n8
- ↑ https://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/col_alg_tut44_logprop.htm
About This Article
Article Summary
X
To solve a logarithm, start by identifying the base, which is "b" in the equation, the exponent, which is "y," and the exponential expression, which is "x." Then, move the exponential expression to one side of the equation, and apply the exponent to the base by multiplying the base by itself the number of times indicated in the exponent. Finally, rewrite your final answer as an exponential expression. To learn how to solve for "x" in a logarithm, scroll down!
Did this summary help you?
Thanks to all authors for creating a page that has been read 284,029 times.
Reader Success Stories
- "A friend who is in school is having trouble understanding how to work out log problems and asked for my help. I haven't used logarithms in ages and forgot how they work. I was clueless until I reviewed this article and got up to scratch. It earned me a kiss." ..." more
Advertisement
"A friend who is in school is having trouble understanding how to work out log problems and asked for my help. I haven't used logarithms in ages and forgot how they work. I was clueless until I reviewed this article and got up to scratch. It earned me a kiss."
..."
more
"Looked everywhere all over the internet for help in my Algebra college class, and I haven't found simple understanding methods until now with wikiHow. Thank you so much. Please continue sending me helpful tips in Algebra. I appreciate you!"
..."
more
"wikiHow has helped me a lot in my studies. Because of this I am able to get good marks in studies. Thanks to you and your whole team."
..."
more
"Thanks a lot sir, these methods were very helpful In my opinion! "
"The first and second methods of the logarithm impress me."
